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  #16  
Old 04-05-2003, 10:34 AM
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The existing value kicks in earlier in the rev range... it allows the "clutch" (torque converter) to slip, giving you the torque of the higher rpm at which your are suddenly running the motor, at the lower (but increasing) speed at which the car is traveling.

It's just a way to deliver torque more immediately to the wheels without the motor waiting for the car to "catch up". No additional torque or power is being "created"... just delivered differently.
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  #17  
Old 04-05-2003, 11:11 AM
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Thanks for the explonation Porter!!

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  #18  
Old 04-05-2003, 05:57 PM
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Quote:
Originally posted by Porter
The existing value kicks in earlier in the rev range... it allows the "clutch" (torque converter) to slip, giving you the torque of the higher rpm at which your are suddenly running the motor, at the lower (but increasing) speed at which the car is traveling.

It's just a way to deliver torque more immediately to the wheels without the motor waiting for the car to "catch up". No additional torque or power is being "created"... just delivered differently.
Gid'ay Jason, You are right on what you are trying to say, just need the right words.

The torque converter can be considered as a separate gear box, between the engine and the gear box, that can change it's ratios from 1:1 to 2:1.

This depends on the load that it has applied to it. When the pedal is floored at take off, the engine rpm will rise to about 2200 to 2500 rpm, this has the torque converter at stall speed.

The Impeller is spinning fast , the Turbine is stopped, so the third element, the Stator is used to multiply the torque by about 2:1. This reduction ratio reduces to 1:1 as the speed difference between the two halves of the torque converter comes up to 1:1.

The overall ratio in first gear is 10.9:1. At stall speed at launch, the ratio goes to 21.8, then as the speed difference comes up to 1:1, the gearbox goes through all the ratios from 21.8 to 10.9

The increase in torque is a function of the ratio.

Harvey.
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  #19  
Old 04-05-2003, 06:17 PM
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don't forget to double pump the accelerator, too!
driving style may have something to do with it, also. my wife's WRX is kinda slow, unless i drive it for a few days. the computer adapts to her "grandma" driving style, but if i drive it for a couple days, it seems to gain about 50hp and turn back into a screamer(although gas mileage goes in the crapper.)
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  #20  
Old 04-05-2003, 07:59 PM
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Quote:
Originally posted by oab_au


Gid'ay Jason, You are right on what you are trying to say, just need the right words.

The torque converter can be considered as a separate gear box, between the engine and the gear box, that can change it's ratios from 1:1 to 2:1.

This depends on the load that it has applied to it. When the pedal is floored at take off, the engine rpm will rise to about 2200 to 2500 rpm, this has the torque converter at stall speed.

The Impeller is spinning fast , the Turbine is stopped, so the third element, the Stator is used to multiply the torque by about 2:1. This reduction ratio reduces to 1:1 as the speed difference between the two halves of the torque converter comes up to 1:1.

The overall ratio in first gear is 10.9:1. At stall speed at launch, the ratio goes to 21.8, then as the speed difference comes up to 1:1, the gearbox goes through all the ratios from 21.8 to 10.9

The increase in torque is a function of the ratio.

Harvey.

Thank you Harvey! I knew someone could be counted on to bring some hard numbers in when I most needed them... Thanks!
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