04-16-2008, 12:34 AM
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Retired
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Join Date: Jan 2007
Location: Orange, CA
Posts: 1,031
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Quote:
Originally Posted by b3lha
Good thinking. I hope it is a linear relationship, but LAN said in another thread that it is not.
If it is a linear relationship I have a doubt about your maths. Or maybe mine. It's late (here) and one or both of us is wrong.
Your x coefficient "5/9" is positive therefore your graph will slope upwards.
But I think it should slope downwards, from (0,50) to (95,0). So the coefficient should be negative. By my reckoning the equation would be y=(-5/9)x + (475/9). Your x=65 would give y=17, therefore 83:17 torque split.
Or, if the known points are actually (0,50) and (100,0) [which makes more sense, 100% duty = FWD] it becomes easier y=(-1/2)x + 50. Then x=65 gives y=18, therefore 82:18 torque split.
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Sorry! You're right, I was just really tired. I re-did the math by hand at work and got the same equation you did, with the same results. I feel embarrassed.
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