[Dessertrunner]

Okay the top row is relationship to the current position of the thermostate being in the front of the water pump.
In this example set the RPM to 3,000rpm, radiator at 78 engine at 90

- When you change the rpm the total litre per min that the engine CAN pump goes up this number is the sum of the Radiator lpm & Engine lpm, in this example its 75 radiator plus 25 engine. Giving a total possiable flow of 100 lpm.
- The 25lpm in the "Engine bypass pipe" assumes that the amount of coolant being sent back to the engine throught the small pipes. THsi amount does not change when the pump flow increase due to the fact that it has high pressure lost throught the pipes and that these pipes are taken off after the heads.

What tends to screw with our heads and is hard to come to terms with is that in the example if we look in the "Flow throught engine block" section its a 100 lpm and Kcal square is 1200. Now lower radiator number from 78c to 60. What you now see is that the flow drops to 42lpm and the Kcal down to 500.

This result sends our heads spinning because it doesn't make sense Clearly this is the issue with have with the thermostate on the water pump. It get feed with cold and hot water at the same time there for if the average temp of the twin liquids mixed that opens or closed the thermostate. Its not the temp of the return coolat from the block.

Hope that help start the discussion.
Tony